=========================preview======================
(PHYS1114)[2013](sum)final~=mval3p^_58026.pdf
Back to PHYS1114 Login to download
======================================================
Name: _________________________ ID: _________________________
Dielectric
\sin \theta \pm \sin \varphi = 2 \sin\left( \frac{\theta \pm \varphi}{2} \right) \cos\left( \frac{\theta \mp \varphi}{2} \right)
\cos \theta + \cos \varphi = 2 \cos\left( \frac{\theta + \varphi} {2} \right) \cos\left( \frac{\theta - \varphi}{2} \right)
cm
\cos \theta - \cos \varphi = -2\sin\left( {\theta + \varphi \over 2}\right) \sin\left({\theta - \varphi \over 2}\right)
( cm mm)
http://www.learner.org/courses/physics/visual/img_lrg/michelson.jpg


d





. . . . .

. . . . .

. . . . .

. . . . .

. . . . .




x

y

z .

..

..










PHYS 1114 General Physics II (Summer 2013) Final Exam, August 8th, 2013



d
















C1
L1
R1
Vs (AC)











C2
L2
R2











a

b

b


Full marks: 105 points (5 bonus points) Time allowed: 3 hours


mirror surface





..






Answer all questions and show all the steps on the answer book provided. ONLY the steps and the answers in the answer book will be graded. Give your numerical answers in at least 3 significant figures.

Constants and Useful Formulae:
C2/Nm2 C Nm2/C2 T m/A
m/s


Question 1 (5pt)
One of the mirrors of a Michelson interferometer is installed incorrectly with an offset of 1 mm shorter from the beam splitter than that of the other mirror. To compensate the shorten path, a rectangular dielectric block with dielectric constant is inserted in the Michelson interferometer as shown below.

A monochromatic light of wavelength of nm is used. Find a value of , which restores the bright spot in the photo-detector.

Question 2 (10pt)
(5pt) For a double slit diffraction and interference pattern, what is the ratio such that the first order maximum of interference pattern overlaps with the first order minimum of the single slit diffraction pattern?
(5pt) When that occurs, show that the intensity of the double slit diffraction and interference pattern equals to the intensity of the single slit diffraction. What is the slit size corresponding this single slit pattern?


Question 3 (15pt)
A rigid square conducting loop with length is released from at rest under gravity, . . as shown in the figure. In addition to gravity, there is a magnetic field .. .. The wire has a mass and a resistance . Assume